I have two very simple models. In my Post
model there are supposed to be two relationships into the User
table. One is for the owner of the post and one is for the last editor of the post. They can be different values, but both refer to the same User
table.
My models are set up like this
class Post(Base): last_editor_id = Column(BigInteger, ForeignKey('users.id'), nullable=True) last_editor = relationship('User', backref='posts', foreign_keys=[last_editor_id]) owner_id = Column(BigInteger, ForeignKey('users.id'), nullable=False, index=True) owner = relationship('User', backref='posts', foreign_keys=[owner_id]) class User(Base): '''This represents a user on the site''' __tablename__ = 'users' id = Column(BigInteger, primary_key=True, unique=True) name = Column(BigInteger, nullable=False)
When I attempt to create these models though, I get the following error
sqlalchemy.exc.ArgumentError: Error creating backref 'posts' on relationship 'Post.owner': property of that name exists on mapper 'Mapper|User|users'
How do I correct this so that I can maintain both forgeign keys in the Post
model?
The error is telling you that you've used post
as a name more then once for your backrefs, all you need to do is give the backref's unique names. Here's a complete example-- I've added a id primary key to the Post class, and also some __repr__
s so we get some readable output.
from sqlalchemy import create_engine from sqlalchemy.ext.declarative import declarative_base from sqlalchemy import Column, BigInteger, ForeignKey, Integer from sqlalchemy.orm import relationship, sessionmaker Base = declarative_base() engine = create_engine('sqlite://') ## In Memory. Session = sessionmaker() Session.configure(bind=engine) session = Session() class Post(Base): __tablename__ = 'post' id = Column(Integer, primary_key=True) last_editor_id = Column(BigInteger, ForeignKey('users.id'), nullable=True) last_editor = relationship('User', backref='editor_posts', foreign_keys=[last_editor_id]) owner_id = Column(BigInteger, ForeignKey('users.id'), nullable=False, index=True) owner = relationship('User', backref='owner_posts', foreign_keys=[owner_id]) def __repr__(self): return '<Post: {}>'.format(self.id) class User(Base): '''This represents a user on the site''' __tablename__ = 'users' id = Column(BigInteger, primary_key=True, unique=True) name = Column(BigInteger, nullable=False) def __repr__(self): return '<User: {}>'.format(self.name) Base.metadata.create_all(engine) bob = User(name='Bob', id=1) alice = User(name='Alice', id=2) post = Post(owner=alice, last_editor=bob, id=1) session.add(post) session.commit() bob = session.query(User).get(1) print bob # <User: Bob> print bob.editor_posts # [<Post: 1>] print bob.owner_posts # [] post = session.query(Post).get(1) print post.owner # <User: Alice> print post.last_editor # <User: Bob>
Now when you query a user, you can ask that object user.owner_posts
or user.editor_posts
.
In general it's a naming Problem of the backref.
Since 1:n relationships are sometimes a bit confusing, I set the relationship attribute always on the singular site, to avoid confusion.
then the backref name is always singular. and the relationship attribute is always in the Class where the foreignkey is referencing to.
Now to my suggestion for the fixed code:
class Post(Base): last_editor_id = Column(BigInteger, ForeignKey('users.id'), nullable=True) owner_id = Column(BigInteger, ForeignKey('users.id'), nullable=False, index=True) class User(Base): '''This represents a user on the site''' __tablename__ = 'users' id = Column(BigInteger, primary_key=True, unique=True) name = Column(BigInteger, nullable=False) owned_posts = relationship('Post', backref='owner') edited_posts = relationship('Post', backref='last_editor')
Now you can get all the owned posts of a User
with User.owned_posts
and all owners of a post with Post.owner
. Same with the last_edited attribute.
For additional info you could read the docs how to set up relationships
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