Can you gulp clean all files in a directory except for a single file?

Question

Is there a way to use gulp-clean such that instead of passing in the files or directories I want to delete, to delete everything that does not match a specific file name in the directory?

For example, If I have 3 files in directory "dir":

dir/a.js dir/b.js dir/c.js 

Sample Pseudocode of what I want to do, (delete everything in /dir/ thats not a.js:

gulp.src('!./dir/a.js').pipe(clean()); 

Answer 1

This should work:

var gulp = require('gulp'); var del = require('del');  gulp.task('clean', function(cb) {     del(['dir/**/*', '!dir/a.js'], cb); }); 

If the excluded file is in a sub directory you need to exclude that dir from deletion. For example:

del(['dir/**/*', '!dir/subdir', '!dir/subdir/a.js'], cb);

or:

del(['dir/**/*', '!dir/subdir{,/a.js}'], cb);

Answer 2

gulp-filter can be used to filter files from a gulp stream:

var gulp = require('gulp'); var filter = require('gulp-filter');  gulp.src('**/*.js')     .pipe(filter(['*', '!dir/a.js']))     .pipe(clean());