SQL ORDER BY route information

Question

Ik have a table with route information in random order, like this:

from    to      street
----------------------------------
92      91      Lange Poten
100     104     Bagijnestraat
85      79      Korte Poten
91      85      Plein
79      100     Bezuidenhoutseweg

I'm trying to find a method to sort it using the route information, where the to column of the current row matches with the from column of the next row. In the example, the order I want is:

from    to      street
----------------------------------
92      91      Lange Poten
91      85      Plein
85      79      Korte Poten
79      100     Bezuidenhoutseweg
100     104     Bagijnestraat

A simple ORDER BY on the from or to column doesn't work because a numerical order isn't the right one. I'm trying to find a method using SQL or Excel.

SQL Fiddle here: http://sqlfiddle.com/#!2/9ebbb

Answer 1

This works in oracle

select a.*
from route  a
start with a.rowid = (select min(rowid) from route )
connect by prior a.t = a.f; 

Answer 2

SQL Server (2005+) it will be

Declare @Routes Table([from] int, [to] int, [street] varchar(17))   
INSERT INTO @Routes VALUES
(92, 91, 'Lange Poten'),
(100, 104, 'Bagijnestraat'),
(85, 79, 'Korte Poten'),
(91, 85, 'Plein'),
(79, 100, 'Bezuidenhoutseweg')

;With  Cte AS
(
    SELECT  [from]
            ,[to]
            ,[street]
    FROM    @Routes
    WHERE   [from] = 92
    UNION ALL
    SELECT  r.[from]
            ,r.[to]
            ,r. [street]
FROM    @Routes AS r
JOIN    Cte c
ON      c.[to] = r.[from]
)

Select * From Cte