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The addition of a slash at the end of a URL instructs the web server to search for a directory. This speeds the web page loading because the server will retrieve the content of the web page without wasting time searching for the file.
A double slash in the URL path is valid and will respond in the browser, but is typically unwelcome, as this could cause duplicate content issues if the CMS delivers the same content on two URLs (i.e. single slash and double slash).
Unfortunately, we soon find out that this returns a 404 if the PathVariable contains a slash. The slash character is the URI standard path delimiter, and all that goes after it counts as a new level in the path hierarchy. As expected, Spring follows this standard.
Solution 1. The backslash ( "\" ) character is a special escape character used to indicate other special characters such as new lines ( \n ), tabs ( \t ), or quotation marks ( \" ). If you want to include a backslash character itself, you need two backslashes or use the @ verbatim string: "\\Tasks" or @"\Tasks" .
You need to escape the slashes as %2F.
You could easily replace the forward slashes / with something like an underscore _ such as Wikipedia uses for spaces. Replacing special characters with underscores, etc., is common practice.
You need to escape those but don't just replace it by %2F manually. You can use URLEncoder for this.
Eg URLEncoder.encode(url, "UTF-8")
Then you can say
yourUrl = "www.musicExplained/index.cfm/artist/" + URLEncoder.encode(VariableName, "UTF-8")
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