Skip first line(field) in loop using CSV file? [duplicate]

Question

Possible Duplicate: When processing CSV data, how do I ignore the first line of data?

I am using python to open CSV file. I am using formula loop but I need to skip the first row because it has header.

So far I remember was something like this but it is missing something: I wonder if someone knows the code for what I am trying to do.

for row in kidfile:
    if row.firstline = false:  # <====== Something is missing here.
        continue
    if ......

Answer 1

There are many ways to skip the first line. In addition to those said by Bakuriu, I would add:

with open(filename, 'r') as f:     next(f)     for line in f: 

and:

with open(filename,'r') as f:     lines = f.readlines()[1:] 

Answer 2

The best way of doing this is skipping the header after passing the file object to the csv module:

with open('myfile.csv', 'r', newline='') as in_file:     reader = csv.reader(in_file)     # skip header     next(reader)     for row in reader:         # handle parsed row 

This handles multiline CSV headers correctly.

---

Older answer:

Probably you want something like:

firstline = True for row in kidfile:     if firstline:    #skip first line         firstline = False         continue     # parse the line 

An other way to achive the same result is calling readline before the loop:

kidfile.readline()   # skip the first line for row in kidfile:     #parse the line 

Answer 3

csvreader.next() Return the next row of the reader’s iterable object as a list, parsed according to the current dialect.