You can use a continue statement in Python to skip over part of a loop when a condition is met. Then, the rest of a loop will continue running. You use continue statements within loops, usually after an if statement.
The continue statement in Python is used to skip the rest of the code inside a loop for the current iteration only. In other words, the loop will not terminate immediately but it will continue on with the next iteration. This is in contrast with the break statement which will terminate the loop completely.
You can use the continue statement if you need to skip the current iteration of a for or while loop and move onto the next iteration.
To skip the first element in Python you can simply write
for car in cars[1:]:
# Do What Ever you want
or to skip the last elem
for car in cars[:-1]:
# Do What Ever you want
You can use this concept for any sequence
(not for any iterable
though).
The other answers only work for a sequence.
For any iterable, to skip the first item:
itercars = iter(cars)
next(itercars)
for car in itercars:
# do work
If you want to skip the last, you could do:
itercars = iter(cars)
# add 'next(itercars)' here if you also want to skip the first
prev = next(itercars)
for car in itercars:
# do work on 'prev' not 'car'
# at end of loop:
prev = car
# now you can do whatever you want to do to the last one on 'prev'
The best way to skip the first item(s) is:
from itertools import islice
for car in islice(cars, 1, None):
pass
# do something
islice
in this case is invoked with a start-point of 1
, and an end point of None
, signifying the end of the iterable
.
To be able to skip items from the end of an iterable
, you need to know its length (always possible for a list, but not necessarily for everything you can iterate on). for example, islice(cars, 1, len(cars)-1)
will skip the first and last items in cars
.
Here is a more general generator function that skips any number of items from the beginning and end of an iterable:
def skip(iterable, at_start=0, at_end=0):
it = iter(iterable)
for x in itertools.islice(it, at_start):
pass
queue = collections.deque(itertools.islice(it, at_end))
for x in it:
queue.append(x)
yield queue.popleft()
Example usage:
>>> list(skip(range(10), at_start=2, at_end=2))
[2, 3, 4, 5, 6, 7]
for item in do_not_use_list_as_a_name[1:-1]:
#...do whatever
Example:
mylist=['one','two','three','four','five']
for i in mylist[1:]:
print(i)
In python index start from 0, We can use slicing operator to make manipulations in iteration.
for i in range(1,-1):
Here's my preferred choice. It doesn't require adding on much to the loop, and uses nothing but built in tools.
Go from:
for item in my_items:
do_something(item)
to:
for i, item in enumerate(my_items):
if i == 0:
continue
do_something(item)
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