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Simple logical operators in Bash

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What does [- Z $1 mean in bash?

$1 means an input argument and -z means non-defined or empty. You're testing whether an input argument to the script was defined when running the script. Follow this answer to receive notifications.

What are logical operators in Linux?

Logical Operators : They are also known as boolean operators. These are used to perform logical operations. They are of 3 types: Logical AND (&&): This is a binary operator, which returns true if both the operands are true otherwise returns false.

What is || in bash script?

Logical OR Operator ( || ) in Bash It is usually used with boolean values and returns a boolean value. It returns true if at least one of the operands is true. Returns false if all values are false.

What does += mean in bash?

The += and -= Operators These operators are used to increment/decrement the value of the left operand with the value specified after the operator. ((i+=1)) let "i+=1"


What you've written actually almost works (it would work if all the variables were numbers), but it's not an idiomatic way at all.

  • (…) parentheses indicate a subshell. What's inside them isn't an expression like in many other languages. It's a list of commands (just like outside parentheses). These commands are executed in a separate subprocess, so any redirection, assignment, etc. performed inside the parentheses has no effect outside the parentheses.
    • With a leading dollar sign, $(…) is a command substitution: there is a command inside the parentheses, and the output from the command is used as part of the command line (after extra expansions unless the substitution is between double quotes, but that's another story).
  • { … } braces are like parentheses in that they group commands, but they only influence parsing, not grouping. The program x=2; { x=4; }; echo $x prints 4, whereas x=2; (x=4); echo $x prints 2. (Also braces require spaces around them and a semicolon before closing, whereas parentheses don't. That's just a syntax quirk.)
    • With a leading dollar sign, ${VAR} is a parameter expansion, expanding to the value of a variable, with possible extra transformations.
  • ((…)) double parentheses surround an arithmetic instruction, that is, a computation on integers, with a syntax resembling other programming languages. This syntax is mostly used for assignments and in conditionals.
    • The same syntax is used in arithmetic expressions $((…)), which expand to the integer value of the expression.
  • [[ … ]] double brackets surround conditional expressions. Conditional expressions are mostly built on operators such as -n $variable to test if a variable is empty and -e $file to test if a file exists. There are also string equality operators: "$string1" == "$string2" (beware that the right-hand side is a pattern, e.g. [[ $foo == a* ]] tests if $foo starts with a while [[ $foo == "a*" ]] tests if $foo is exactly a*), and the familiar !, && and || operators for negation, conjunction and disjunction as well as parentheses for grouping. Note that you need a space around each operator (e.g. [[ "$x" == "$y" ]], not [[ "$x"=="$y" ]]), and a space or a character like ; both inside and outside the brackets (e.g. [[ -n $foo ]], not [[-n $foo]]).
  • [ … ] single brackets are an alternate form of conditional expressions with more quirks (but older and more portable). Don't write any for now; start worrying about them when you find scripts that contain them.

This is the idiomatic way to write your test in bash:

if [[ $varA == 1 && ($varB == "t1" || $varC == "t2") ]]; then

If you need portability to other shells, this would be the way (note the additional quoting and the separate sets of brackets around each individual test, and the use of the traditional = operator rather than the ksh/bash/zsh == variant):

if [ "$varA" = 1 ] && { [ "$varB" = "t1" ] || [ "$varC" = "t2" ]; }; then

very close

if [[ $varA -eq 1 ]] && [[ $varB == 't1' || $varC == 't2' ]]; 
  then 
    scale=0.05
  fi

should work.

breaking it down

[[ $varA -eq 1 ]] 

is an integer comparison where as

$varB == 't1'

is a string comparison. otherwise, I am just grouping the comparisons correctly.

Double square brackets delimit a Conditional Expression. And, I find the following to be a good reading on the subject: "(IBM) Demystify test, [, [[, ((, and if-then-else"


A very portable version (even to legacy bourne shell):

if [ "$varA" = 1 -a \( "$varB" = "t1" -o "$varB" = "t2" \) ]
then    do-something
fi

This has the additional quality of running only one subprocess at most (which is the process [), whatever the shell flavor.

Replace = with -eq if variables contain numeric values, e.g.

  • 3 -eq 03 is true, but
  • 3 = 03 is false. (string comparison)

Here is the code for the short version of if-then-else statement:

( [ $a -eq 1 ] || [ $b -eq 2 ] ) && echo "ok" || echo "nok"

Pay attention to the following:

  1. || and && operands inside if condition (i.e. between round parentheses) are logical operands (or/and)

  2. || and && operands outside if condition mean then/else

Practically the statement says:

if (a=1 or b=2) then "ok" else "nok"