Set value for particular cell in pandas DataFrame using index

Question

I have created a Pandas DataFrame

df = DataFrame(index=['A','B','C'], columns=['x','y']) 

and have got this

     x    y A  NaN  NaN B  NaN  NaN C  NaN  NaN 

Now, I would like to assign a value to particular cell, for example to row C and column x. I would expect to get this result:

     x    y A  NaN  NaN B  NaN  NaN C  10  NaN 

with this code:

df.xs('C')['x'] = 10 

However, the contents of df has not changed. The dataframe contains yet again only NaNs.

Any suggestions?

Answer 1

RukTech's answer, df.set_value('C', 'x', 10), is far and away faster than the options I've suggested below. However, it has been slated for deprecation.

Going forward, the recommended method is .iat/.at.

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Why df.xs('C')['x']=10 does not work:

df.xs('C') by default, returns a new dataframe with a copy of the data, so

df.xs('C')['x']=10 

modifies this new dataframe only.

df['x'] returns a view of the df dataframe, so

df['x']['C'] = 10 

modifies df itself.

Warning: It is sometimes difficult to predict if an operation returns a copy or a view. For this reason the docs recommend avoiding assignments with "chained indexing".

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So the recommended alternative is

df.at['C', 'x'] = 10 

which does modify df.

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In [18]: %timeit df.set_value('C', 'x', 10) 100000 loops, best of 3: 2.9 µs per loop  In [20]: %timeit df['x']['C'] = 10 100000 loops, best of 3: 6.31 µs per loop  In [81]: %timeit df.at['C', 'x'] = 10 100000 loops, best of 3: 9.2 µs per loop