Centos / Linux Bash
I have a log file, which has lots of text in and epoch numbers all over the place. I want to replace all epochs whereever they are into readable date/time.
I've been wanting to this via sed, as that seems the tool for the job. I can't seem to get the replacement part of sed to actually parse the variable(epoch) to it for conversion.
Sample of what I'm working with...
echo "Some stuff 1346474454 And not working" \
| sed 's/1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]/'"`bpdbm -ctime \&`"'/g'
Some stuff 0 = Thu Jan 1 01:00:00 1970 And not working
The bpdbm part will convert a supplied epoch variable into useful date. Like this..
bpdbm -ctime 1346474454
1346474454 = Sat Sep 1 05:40:54 2012
So how do i get the "found" item to be parsed into a command. As i don't seem to be able to get it to work.
Any help would be lovely. If there is another way, that would be cool...but i suspect sed will be quickest.
Thanks for your time!
that seems the tool for the job
No, it is not. sed
can use &
only itself, there is no way how to make it an argument to a command. You need something more powerful, e.g. Perl:
perl -pe 'if ( ($t) = /(1[0-9]+)/ ) { s/$t/localtime($t)/e }'
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