Search array return index in bash

Question

Just pesuocode but this is essentially what I would like to do.

Array=("1" "Linux" "Test system"
       "2" "Windows" "Workstation"
       "3" "Windows" "Workstation")


echo "number " ${array[search "$1"]} "is a" ${array[search "$1" +1]} ${array[search "$1" +2])}

Is this possible with bash? I could only find info on search and replace. I didn't see anything That would return and index.

Answer 1

Something like that should work:

search() {
    local i=1;
    for str in "${array[@]}"; do
        if [ "$str" = "$1" ]; then
            echo $i
            return
        else
            ((i++))
        fi
    done
    echo "-1"
}

While looping over the array to find the index is certainly possible, this alternative solution with an associative array is more practical:

array=([1,os]="Linux"   [1,type]="Test System"
       [2,os]="Windows" [2,type]="Work Station"
       [3,os]="Windows" [3,type]="Work Station")

echo "number $1 is a ${array[$1,os]} ${array[$1,type]}"

Answer 2

You could modify this example from this link to return an index without much trouble:

# Check if a value exists in an array
# @param $1 mixed  Needle  
# @param $2 array  Haystack
# @return  Success (0) if value exists, Failure (1) otherwise
# Usage: in_array "$needle" "${haystack[@]}"
# See: http://fvue.nl/wiki/Bash:_Check_if_array_element_exists
in_array() {
    local hay needle=$1
    shift
    for hay; do
        [[ $hay == $needle ]] && return 0
    done
    return 1
}