Which would be the most efficient way to convert a squared matrix like
1 2 3
4 5 6
7 8 9
into
[1 2 3 4 5 6 7 8 9]
in c#
I was doing
int[,] array2D = new int[,] { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } };
int[] array1D = new int[9];
int ci=0;
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
array1D[ci++] = array2D[i, j]);
}
}
LINQ makes this trivial.
int[,] array2d = ...;
var array1d = array2d.Cast<int>().ToArray();
Otherwise, your way is adequate but could be generalized:
int[,] array2d = ...;
var rows = array2d.GetLength(0);
var cols = array2d.GetLength(1);
var array1d = new int[rows * cols];
var current = 0;
for (int i = 0; i < rows; i++)
{
for (int j = 0; j < cols; j++)
{
array1d[current++] = array2d[i, j];
}
}
Or even:
int[,] array2d = ...;
var array1d = new int[array2d.GetLength(0) * array2d.GetLength(1)];
var current = 0;
foreach (var value in array2d)
{
array1d[current++] = value;
}
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