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I have a bunch of files in a directory all named YYYY_MM_DD
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_05
-rw-r--r-- 1 root root 483K Apr 21 13:17 2012_04_06
-rw-r--r-- 1 root root 484K Apr 21 13:17 2012_04_07
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_08
-rw-r--r-- 1 root root 344K Apr 21 13:17 2012_04_09
-rw-r--r-- 1 root root 66K Apr 21 13:17 2012_04_10
-rw-r--r-- 1 root root 461K Apr 21 13:17 2012_04_11
-rw-r--r-- 1 root root 475K Apr 21 15:09 2012_04_17
-rw-r--r-- 1 root root 480K Apr 21 15:10 2012_04_18
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_19
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_20
I have a shell script that accepts a file as a paramater and calculates figures based on the data in the file, i call the script like this
sh Calculate.sh MyFile
I want to run this shell script for every file in this directory.
How would i go about doing this, xargs ??
955
To loop through a directory, and then print the name of the file, execute the following command: for FILE in *; do echo $FILE; done.
The syntax to loop through each file individually in a loop is: create a variable (f for file, for example). Then define the data set you want the variable to cycle through. In this case, cycle through all files in the current directory using the * wildcard character (the * wildcard matches everything).
We can run all scripts in a directory or path using "run-parts" command. The run-parts command is used to run scripts or programs in a directory or path. One disadvantage with run-parts command is it won't execute all scripts. It will work only if your scripts have the correct names.
Have you tried the find command with execution ?
My sample will echo the files, but you can call a shell script with the filename as a parameter
find . -maxdepth 1 -type f -exec echo {} \;
A simple for loop in the shell:
for file in *; do sh Calculate.sh "$file"; done
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