0) I am using Retrofit 2 for work with Bank API.
1) I have some interface:
public interface ApiService {
@GET("statdirectory/exchange")
Call<List<MyModel>> getСurrency(@Query("date") String inputDate);
}
2) And when i call method getСurrency(someParametr), where someParametr is string, consist with "date&json" (for example, "20170917&json"):
ApiService apiService = RetrofitController.getApi();
apiService.getCurrency("20170917&json").enqueue(new Callback<List<MyModel>>() {
@Override
public void onResponse(Call<List<MyModel>> call, Response<List<MyModel>> response) {
call.request().url();
Log.e("URL", call.request().url()+"");
response.code();
Log.e("CODE", response.code()+"");
}
//.....
3) I see that:
URL: "https://bank.gov.ua/NBUStatService/v1/statdirectory/exchange?date=20170917%26json" (& is replaced by %26)
CODE: "404"
4) Inmy interface i add encoded:
getСurrency(@Query(value="date", encoded=false) String inputDate);
But my result is the same as in step 3!
5) How to check this problem? How to get URL without %26 on my string? I read other questions with similar problem, but isn't solve my problem. Thanks!
I just wanted to clarify that the original problem was that the encoded parameter needed to be true: encoded=
true. This indicates that the value provided is already encoded and thus doesn't need to be re-encoded by retrofit. As is stated in the retrofit documentation, the default value of encoded
is false. ie:
getСurrency(@Query(value="date", encoded=true) String inputDate);
will result in the correct url being generated.
The documentation states the following regarding the encoded
parameter:
Specifies whether the parameter name and value are already URL encoded.
Source: https://square.github.io/retrofit/2.x/retrofit/index.html?retrofit2/http/Query.html
As noted here https://github.com/square/okhttp/issues/2623 by swankjesse
Use HttpUrl to build the url
HttpUrl url = HttpUrl.parse("https://bank.gov.ua/NBUStatService/v1/statdirectory/exchange?date=20170916&json");
Then change your method call to
@GET
Call<List<MyModel>> getСurrency(@Url String ur);
Then
apiService.getCurrency(url.toString())
.enqueue(new Callback<List<MyModel>>() {
@Override
public void onResponse(Call<List<MyModel>> call, retrofit2.Response<List<MyModel>> response) {
// your response
}
@Override
public void onFailure(Call<List<MyModel>> call, Throwable t) {
}
});
Other way is to use Okhttp's Interceptor and replace %26 by &
class MyInterceptor implements Interceptor {
@Override
Response intercept(Interceptor.Chain chain) throws IOException {
Request request = chain.request()
String stringurl = request.url().toString()
stringurl = stringurl.replace("%26", "&")
Request newRequest = new Request.Builder()
.url(stringurl)
.build()
return chain.proceed(newRequest)
}
}
Then
OkHttpClient client = new OkHttpClient.Builder();
client.addInterceptor(new MyInterceptor());
If you still got this problem, I have 2 solutions.
FIRST SOLUTION:
// Create a URL object and pass to constructor your url
URL urlObject = new URL(url);
// Create connection
HttpURLConnection connection = (HttpURLConnection) urlObject.openConnection();
// SET 'GET' request
connection.setRequestMethod("GET");
connection.connect();
// Create stream to read output
InputStream inputStream = connection.getInputStream();
// Craete buffer to gain all output
StringBuffer stringBuffer = new StringBuffer();
AND HERE IS THE KEY
YOU CREATE A BUFFERREADER AND SET CP1251 SO URL`S GONNA BE ENCODED
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream, "cp1251"));
// Read untill end
String line;
while ((line = bufferedReader.readLine()) != null) {
stringBuffer.append(line);
}
// HERE IS YOUR JSON RESULT
resultJson = stringBuffer.toString();
SECOND SOLUTION:
Just add encoded = true
to your @Query
annotation
@GET("some_path")
Call<RequestBody> function(@Query(value = "param", encoded = true) String your_param);
That's it! All that worked well for me. If you have some comments or questions, I will answer them.
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