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I just ran into the problem that the split method for strings wouldn't work with character "|" as an argument. It somehow separates each character in the string.
Code:
String[] res = "12345|6".split("|");
Log.d("split", Arrays.toString(res));
Output:
split﹕ [, 1, 2, 3, 4, 5, |, 6]
569
1.1. Method Syntax The split () method is overloaded: Watch out that split () throws PatternSyntaxException if the regular expression’s syntax is invalid. In given example, " [" is invalid regular expression. Program output. Method does not accept 'null' argument.
The string split () method breaks a given string around matches of the given regular expression. For Example: Input String: 016-78967 Regular Expression: - Output : {"016", "78967"} Following are the two variants of split () method in Java: 1. Public String [ ] split ( String regex, int limit )
string - The split () method in Java does not work on a dot (.) - Stack Overflow Bookmark this question. Show activity on this post. How can I use "." as the delimiter with String.split () in java [duplicate] (8 answers)
In this tutorial, learn how to split a string into an array in Java with the delimiter. 1. String split () Method Use split () to split a string into a string array by tokenizing with delimiter or regular expression. 1.1. Method Syntax The split () method is overloaded:
Use escape character before | like below:
String[] res = "12345|6".split("\\|");
Similar "escape character logic" is required, when you are dealing/splitting with any of the below special characters (used by Regular Expression):
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