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Resolving circular dependencies by linking the same library twice?

We have a code base broken up into static libraries. Unfortunately, the libraries have circular dependencies; e.g., libfoo.a depends on libbar.a and vice-versa.

I know the "correct" way to handle this is to use the linker's --start-group and --end-group options, like so:

g++ -o myApp -Wl,--start-group -lfoo -lbar -Wl,--end-group 

But in our existing Makefiles, the problem is typically handled like this:

g++ -o myApp -lfoo -lbar -lfoo 

(Imagine this extended to ~20 libraries with complex interdependencies.)

I have been going through our Makefiles changing the second form to the first, but now my co-workers are asking me why... And other than "because it's cleaner" and a vague sense that the other form is risky, I do not have a good answer.

So, can linking the same library multiple times ever create a problem? For example, could the link fail with multiply-defined symbols if the same .o gets pulled in twice? Or is there any risk we could wind up with two copies of the same static object, creating subtle bugs?

Basically, I want to know if there is any possibility of link-time or run-time failures from linking the same library multiple times; and if so, how to trigger them. Thanks.

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Nemo Avatar asked Feb 21 '12 15:02

Nemo


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2 Answers

The problem with

g++ -o myApp -lfoo -lbar -lfoo 

is that there is no guarantee, that two passes over libfoo and one pass over libbar are enough.

The approach with Wl,--start-group ... -Wl,--end-group is better, because more robust.

Consider the following scenario (all symbols are in different object-files):

  • myApp needs symbol fooA defined in libfoo.
  • Symbol fooA needs symbol barB defined in libbar.
  • Symbol barB needs symbol fooC defined in libfoo. This is the circular dependency, which can be handled by -lfoo -lbar -lfoo.
  • Symbol fooC needs symbol barD defined in libbar.

To be able to build in the case above, we would need to pass -lfoo -lbar -lfoo -lbar to the linker. Why?

  1. The linker sees libfoo for the first time and uses definitions of symbol fooA but not fooC, because so far it doesn't see a necessity to include also fooC into the binary. The linker however starts to look for definition of barB, because its definition is needed for fooA to function.
  2. The linker sees -libbar, includes the definition of barB (but not barD) and starts to look for definition of fooC.
  3. The definition of fooC is found in libfoo, when it processed for the second time. Now it becomes evident, that also the definition of barD is needed - but too late there is no libbar on the command line anymore!

The example above can be extended to an arbitrary dependency depth (but this happens seldom in real life).

Thus using

g++ -o myApp -Wl,--start-group -lfoo -lbar -Wl,--end-group 

is a more robust approach, because linker passes as often over the library group as needed - only when a pass didn't change the symbol table will the linker move on to the the next library on the command line.

There is however a small performance penalty to pay: in the first example -lbar were scanned once more compared with the manual command line -lfoo -lbar -lfoo. Not sure whether it is worth mentioning/thinking about through.

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ead Avatar answered Sep 18 '22 23:09

ead


All I can offer is a lack of counter-example. I've actually never seen the first form before (even though it's clearly better) and always seen this solved with the second form, and haven't observed problems as a result.

Even so I would still suggest changing to the first form because it clearly shows the relationship between the libraries rather than relying on the linker behaving in a particular way.

That said, I would suggest at least considering if there's a possibility of refactoring the code to pull out the common pieces into additional libraries.

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Mark B Avatar answered Sep 18 '22 23:09

Mark B