GNU C++ how to check when -std=c++0x is in effect?

Question

My system compiler (gcc42) works fine with the TR1 features that I want, but trying to support newer compiler versions other than the systems, trying to accessing TR1 headers an #error demanding the -std=c++0x option because of how it interfaces with library or some hub bub like that.

/usr/local/lib/gcc45/include/c++/bits/c++0x_warning.h:31:2: error: #error This file requires compiler and library support for the upcoming ISO C++ standard, C++0x. This support is currently experimental, and must be enabled with the -std=c++0x or -std=gnu++0x compiler options. 

Having to supply an extra switch is no problem, to support GCC 4.4 and 4.5 under this system (FreeBSD), but obviously it changes the picture!

Using my system compiler (g++ 4.2 default dialect):

#include <tr1/foo> using std::tr1::foo; 

Using newer (4.5) versions of the compiler with -std=c++0x:

#include <foo> using std::foo; 

Is there anyway using the pre processor, that I can tell if g++ is running with C++0x features enabled?

Something like this is what I'm looking for:

#ifdef __CXX0X_MODE__ #endif 

but I have not found anything in the manual or off the web.

At this rate, I'm starting to think that life would just be easier, to use Boost as a dependency, and not worry about a new language standard arriving before TR4... hehe.

Answer 1

There seems, with gcc 4.4.4, to be only one predefined macro hinting that -std=c++0x is in effect:

#define __GXX_EXPERIMENTAL_CXX0X__ 1 

I don't have access to gcc 4.5.0 , but you can check that one yourself:

[16:13:41 0 ~] $ g++ -E -dM -std=c++0x -x c++ /dev/null >b [16:13:44 0 ~] $ g++ -E -dM -std=c++98 -x c++ /dev/null >a [16:13:50 0 ~] $ diff -u a b --- a   2010-06-02 16:13:50.200787591 +0200 +++ b   2010-06-02 16:13:44.456912378 +0200 @@ -20,6 +20,7 @@  #define __linux 1  #define __DEC32_EPSILON__ 1E-6DF  #define __unix 1 +#define __GXX_EXPERIMENTAL_CXX0X__ 1  #define __LDBL_MAX_EXP__ 16384  #define __linux__ 1  #define __SCHAR_MAX__ 127 

For one-line command do,

g++ -E -dM -std=c++98 -x c++ /dev/null > std1 && g++ -E -dM -std=c++0x -x c++ /dev/null > std2 && diff -u std1 std2 | grep '[+|-]^*#define' && rm std1 std2 

gives you something like:

+#define __GXX_EXPERIMENTAL_CXX0X__ 1 

Answer 2

If you compile with -std=c++0x, then __GXX_EXPERIMENTAL_CXX0X__ will be defined.