Require multiple files

Question

I am building a PHP application that uses a select menu to build email templates. The templates are broken into reusable parts (each is a separate html file). Is there an easy way to require multiple files with one expression? (my PHP is really rusty...)

Essentially I want to do something like:

function require_multi() {
    require_once($File1);
    require_once($File2);
    require_once($File3);
    require_once($File4);
}

Answer 1

Well, you could turn it into a function:

function require_multi($files) {
    $files = func_get_args();
    foreach($files as $file)
        require_once($file);
}

Use like this:

require_multi("one.php", "two.php", ..);

However, if you're including classes, a better solution would be to use autoloading.

Answer 2

EDIT:

Because you want to require or include multiple files, you could use this recursive algorithm to include files in a specified folder. The folder is the root that starts the iterator. Because the algorithm is recursive, it will automatically traverse all subsequent folders and include those files as well.

public function include_all_files($root) {
    $d = new RecursiveDirectoryIterator($root);
    foreach (new RecursiveIteratorIterator($d) as $file => $f) {
        $ext = pathinfo($f, PATHINFO_EXTENSION);
        if ($ext == 'php' || $ext == 'inc')
            include_once ($file); // or require(), require_once(), include_once()
    }
}

include_all_files('./lib');

Answer 3

Credit to Tom Haigh from how to require all files in a folder?:

$files = glob( $dir . '/*.php' );
foreach ( $files as $file )
    require( $file );

Store all your required files in $dir and the above code will do the rest.