replace all symlinks with original

Question

I have the following directory structure

/symdir   sym1 -> ../dir1   sym2 -> ../dir2   hello.txt 

And then

/dir1   some   files   here /dir2   more   files 

I would like to replace the symlinks in symdir (sym1, sym2) with the originals. I.e.

some_awesome_bash_func symdir symdir_output 

Would create

/symdir_output   /dir1     some     files     here   /dir2     more     files   hello.txt 

How would I accomplish this?

Answer 1

My very personal trick for files (not directories):

sed -i '' **/* 

Note that I'm using ** which uses the bash globstar option, you may have to enable it beforehand:

shopt -s globstar 

How it works

I trick sed to do the job, by using an implementation detail of the sed inplace mode.

sed is a tool to edit streams of text. The -i option of sed means inplace, the empty string '' is the instruction set: so there's no instruction, sed will do nothing. **/* is a bash globstar pattern meaning "all files and all folders, at all depth, from here".

The algorithm sed uses to edit a file inplace is:

• Create a temporary file as the output file,
• for each line in the input file:
  • apply the transformation, write to the output file.
• Move the output file over the input file.

As I'm asking no transformations (the empty string), the algorithm can be simplified as:

• Create a temporary file,
• copy the content of the original file to the temporary file
• move the temporary file over the original file.

The temporary file is a real file, sed completly ignores that the input file was a symlink, it just reads it. So at the last step, when sed moves the temporary file over the real file, it "overwrite" the symlink with a real file, that's what we wanted.

This also explains why it won't work to transform a "symlink to a directory" to a real directory: sed works on file contents.

Answer 2

You can do this easily with rsync:

rsync symdir/ symdir_output/ -a --copy-links -v 

(-a means preserve basically every detail about the files, --copy-links overrides -a to turn symlinks into the real files/directories, and -v is for verbose)

Edit:

Sorry, my solution doesn't do exactly what you asked for. It will preserve the symlink's names instead of using the destination names. symdir_output would have sym1 and sym2 instead of dir1 and dir2 (though sym1 and sym2 would be a real copy of dir1 and dir2). Hope it still works for you.