I would convert a structured list in a tidy dataFrame using the speed of the dplyr package. I would know if the solution I am posting right now is "state-of-art" or there's something faster.
Here is an example of my starting list:
l = list()
l[[1]] = list(member1=c(a=rnorm(1)),member2=matrix(rnorm(3),nrow=3,ncol=1,dimnames=list(c(letters[2:4]),c("sample"))))
l[[2]] = list(member1=c(a=rnorm(1)),member2=matrix(rnorm(3),nrow=3,ncol=1,dimnames=list(c(letters[2:4]),c("sample"))))
l[[3]] = list(member1=c(a=rnorm(1)),member2=matrix(rnorm(3),nrow=3,ncol=1,dimnames=list(c(letters[2:4]),c("sample"))))
With this result (to show you the toy structure):
l
[[1]]
[[1]]$member1
a
0.3340196
[[1]]$member2
sample
b 1.0098830
c 0.6413375
d 0.9080675
[[2]]
[[2]]$member1
a
0.0590878
[[2]]$member2
sample
b 0.5585736
c -0.5936157
d -0.3985687
[[3]]
[[3]]$member1
a
0.06242458
[[3]]$member2
sample
b -0.2873391
c 0.5326067
d -1.1635551
Now I'll use a convenience function to rearrange the data an lapply
to navigate through the list:
organizeSamples = function(x){
member = x$member2
output = data.frame(key=rownames(member),value=member[,1])
return(output)
}
l_new = lapply(l, organizeSamples)
Now dplyr does the magic:
samples = dplyr::bind_rows(l_new)
samples :
key value
1 b 1.0098830
2 c 0.6413375
3 d 0.9080675
4 b 0.5585736
5 c -0.5936157
6 d -0.3985687
7 b -0.2873391
8 c 0.5326067
9 d -1.1635551
There's a way to do it faster, more elegant & compact using dplyr?
Convert List to DataFrame using data. data. frame() is used to create a DataFrame in R that takes a list, vector, array, etc as arguments, Hence, we can pass a created list to the data. frame() function to convert list to DataFrame. It will store the elements in a single row in the DataFrame.
To sort a data frame in R, use the order( ) function. By default, sorting is ASCENDING. Prepend the sorting variable by a minus sign to indicate DESCENDING order.
Here's another approach with a little more dplyr/tidyr functions and piping, however I haven't tested its performance against the original approach in the question and whether it is more elegant depends on personal preference.
library(dplyr); library(tidyr)
lapply(l, `[[`, 2) %>%
data.frame %>%
add_rownames("key") %>%
gather(x, value, -key) %>%
select(-x)
# key value
#1 b -1.1476570
#2 c -0.2894616
#3 d -0.2992151
#4 b 0.2522234
#5 c -0.8919211
#6 d 0.4356833
#7 b -0.2242679
#8 c 0.3773956
#9 d 0.1333364
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