Removing DUPLICATE rows in hive based on columns

Question

I have a HIVE table with 10 columns where first 9 columns will have duplicate rows while the 10th column will not as it CREATE_DATE which will have the date it was created.

Example:

If I insert 10 rows into the table today it will have the CREATE_DATE as todays date.. If I insert the same 10 rows again tomorrow it will have a different CREATE_DATE which creates the problem of me using DISTINCT..

Is there a way of deleting the duplicate records based on 9 columns and ignoring the 10th.

Example: Lets consider i have 5 columns in the table. This is an EXTERNAL HIVE TABLE partitioned by DAYID and MARKETID. Whenever the columns other than CREATEDATE (as referred by Row 1 and 2) are same OR if the rows are duplicate (as referred by Row 3 and 4) it should retain any one of those rows. Doesn't matter which it retains.

COL1 COL2 CREATEDATE   DAYID    MARKETID  
A     1    20131206   20131207 1234  
A     1    20131207   20131207 1234  
A     1    20131206   20131207 1234  
B     1    20131206   20131207 1234  
B     1    20131206   20131207 1234  
C     2    20131206   20131207 1234  
C     2    20131207   20131207 5678 

output---

COL1 COL2 CREATEDATE   DAYID    MARKETID
A     1    20131206   20131207   1234
B     1    20131206   20131207   1234
C     2    20131206   20131207   1234
C     2    20131207   20131207   5678

Thanks Nates

Answer 1

You can do the following :

select col1,col2,dayid,marketid,max(createdate) as createdate
from tablename
group by col1,col2,dayid,marketid

This way you are grouping the data by all the columns except the data so if there are rows with the same values in these columns they will be in the same group, and then, just "choose" the createdate you want by using an aggregate function like max/min etc.