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Trying to strip the "0b1" from the left end of a binary number.
The following code results in stripping all of binary object. (not good)
>>> bbn = '0b1000101110100010111010001' #converted bin(2**24+**2^24/11)
>>> aan=bbn.lstrip("0b1") #Try stripping all left-end junk at once.
>>> print aan #oops all gone.
''
So I did the .lstrip() in two steps:
>>> bbn = '0b1000101110100010111010001' # Same fraction expqansion
>>> aan=bbn.lstrip("0b")# Had done this before.
>>> print aan #Extra "1" still there.
'1000101110100010111010001'
>>> aan=aan.lstrip("1")# If at first you don't succeed...
>>> print aan #YES!
'000101110100010111010001'
What's the deal?
Thanks again for solving this in one simple step. (see my previous question)
421
There are multiple ways to remove whitespace and other characters from a string in Python. The most commonly known methods are strip() , lstrip() , and rstrip() . Since Python version 3.9, two highly anticipated methods were introduced to remove the prefix or suffix of a string: removeprefix() and removesuffix() .
This can be achieved using C++20 std::string. starts_with() or std::string::substr function. That's all about removing the prefix from a string in C++.
Python String removeprefix() function removes the prefix and returns the rest of the string. If the prefix string is not found, then it returns the original string. It is introduced in Python 3.9. 0 version.
The strip family treat the arg as a set of characters to be removed. The default set is "all whitespace characters".
You want:
if strg.startswith("0b1"):
strg = strg[3:]
No. Stripping removes all characters in the sequence passed, not just the literal sequence. Slice the string if you want to remove a fixed length.
24
In Python 3.9 you can use bbn.removeprefix('0b1').
(Actually this question has been mentioned as part of the rationale in PEP 616.)
22
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