i have a string. I want to delete the last character of the string if it is a space. i tried the following code,
str.erase(remove_if(str.begin(), str.end(), isspace), str.end());
but my g++ compiler gives me an error saying:
error: no matching function for call to ‘remove_if(__gnu_cxx::__normal_iterator<char*,
std::basic_string<char, std::char_traits<char>, std::allocator<char> > >,
__gnu_cxx::__normal_iterator<char*, std::basic_string<char, std::char_traits<char>,
std::allocator<char> > >, <unresolved overloaded function type>)’
please help.
Java Remove Character from String. Java String class has various replace () methods. We can use this to remove characters from a string. The idea is to pass an empty string as a replacement. Let’s look at the replace () methods present in the String class. replace (char oldChar, char newChar): This method returns a new string where oldChar is ...
Below are the steps to remove a specific character using Find and Replace: Select the range of cells you want to work with. Click on Find & Select from the Home tab (under the ‘Editing’ group). This will display a dropdown menu. Select ‘Replace’. This will open the Find and Replace dialog box.
The two methods we used for removing a single character can handle a sequence of characters equally well. To remove specific text from each cell in a selected range, press Ctrl + H to display the Find and Replace dialog, and then: Enter the unwanted text in the Find what box. Leave the Replace with box blank.
The Regex.Replace () function is used to replace two texts in a specified order. We can remove characters from a string by replacing each character with a string.Empty by specifying each character in the regex pattern parameter.
The first problem is that isspace
has multiple overloads in the C++ Standard Library. The initial fix is to provide an explicit type for the function so that the compiler knows which function to take the address of:
#include <string>
#include <algorithm>
#include <cctype>
int main()
{
std::string str = "lol hi innit";
str.erase(std::remove_if(str.begin(), str.end(), (int(*)(int))isspace), str.end());
std::cout << str; // will output: "lolhiinnit"
}
It's a big ugly but, hey, this is C++.
Second, your code will remove all spaces in the string, which is not what you seem to want. Consider a simple if statement on the last character of the string:
#include <string>
#include <cassert>
int main()
{
std::string str = "lol hi innit ";
assert(!str.empty());
if (*str.rbegin() == ' ')
str.resize(str.length()-1);
std::cout << "[" << str << "]"; // will output: "[lol hi innit]"
}
Hope this helps.
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