Relative Path in launchd plist

Question

I am currently using a plist to run a shell script.

 <?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple Computer//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
        <plist version="1.0">
        <dict>
                <key>Label</key>
                <string>com.name.set</string>
                <key>Program</key>
                <string>/Users/username_here/Desktop/simple.sh</string>
                <key>RunAtLoad</key>
                <true/>
                <key>StartInterval</key>
                <integer>5</integer>
                <key>StandardErrorPath</key>
                <string>/tmp/com.name.example.stderr</string>
                <key>StandardOutPath</key>
                <string>/tmp/com.name.example.stdout</string>
        </dict>
        </plist>

This works! But when I change the program name to be

<string>/Desktop/simple.sh</string>

it doesn't run the script. also ~/Desktop/simple.sh does not work.

Is there a way to run the script without knowing the username and using an absolute path?

I am also getting this error message when I tail launchd.

com.apple.xpc.launchd[1] (com.name.example[8178]): Service could not initialize: 14F27: xpcproxy + 13421 [1402][AD0301C4-D364-31CE-8BA7-B5DBECE64D0A]: 0x2

Thanks!

Answer 1

Using a shell as arg0 and giving it a path relative to the user's home folder works for me:

<key>ProgramArguments</key>
<array>
    <string>zsh</string>
    <string>-c</string>
    <string>~/CLI/scripts/list_open_jira_tickets --skip=5297 &gt; ~/CLI/tmp/open_jira_tickets.txt</string>
</array>