Menu
Is it possible to use a regex to match "February 2009", for example?
458
$ means "Match the end of the string" (the position after the last character in the string). Both are called anchors and ensure that the entire string is matched instead of just a substring.
Use the escape character \ to match a period with regex within a regular expression to match a literal period since, by default, the dot . is a metacharacter in regex that matches any character except a newline.
(? i) makes the regex case insensitive. (? c) makes the regex case sensitive.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
Along the lines of
\b(?:Jan(?:uary)?|Feb(?:ruary)?|...|Dec(?:ember)?) (?:19[7-9]\d|2\d{3})(?=\D|$) that's
\b # a word boundary (?: # non-capturing group Jan(?:uary)? # Jan(uary) |Feb(?:ruary)? # |... # and so on |Dec(?:ember)? # Dec(ember) ) # end group # a space (?: # non-capturing group 19[7-9]\d|2\d{3} # 1970-2999 ) # end group (?=\D|$) # followed by: anything but a digit or the end of string
146
I had to work on this to match a few fringe examples, but I ended up using
(\b\d{1,2}\D{0,3})?\b(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|(Nov|Dec)(?:ember)?)\D?(\d{1,2}\D?)?\D?((19[7-9]\d|20\d{2})|\d{2}) to capture dates with word months in them
41
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
