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Using character sets For example, the regular expression "[ A-Za-z] " specifies to match any single uppercase or lowercase letter. In the character set, a hyphen indicates a range of characters, for example [A-Z] will match any one capital letter.
*[A-Z]) represents at least one uppercase character.
To check if a letter in a string is uppercase or lowercase use the toUpperCase() method to convert the letter to uppercase and compare it to itself. If the comparison returns true , then the letter is uppercase, otherwise it's lowercase. Copied!
Symbols, accent marks, and punctuation marks are considered special characters. Similarly, ASCII control characters and formatting characters like paragraph marks are also special characters.
If you need one single regex, try:
(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*\W)
A short explanation:
(?=.*[a-z]) // use positive look ahead to see if at least one lower case letter exists
(?=.*[A-Z]) // use positive look ahead to see if at least one upper case letter exists
(?=.*\d) // use positive look ahead to see if at least one digit exists
(?=.*\W]) // use positive look ahead to see if at least one non-word character exists
And I agree with SilentGhost, \W might be a bit broad. I'd replace it with a character set like this: [-+_!@#$%^&*.,?] (feel free to add more of course!)
Bart Kiers, your regex has a couple issues. The best way to do that is this:
(.*[a-z].*) // For lower cases
(.*[A-Z].*) // For upper cases
(.*\d.*) // For digits
(.*\W.*) // For symbols (non-word characters)
In this way you are searching no matter if at the beginning, at the end or at the middle. In your have I have a lot of troubles with complex passwords.
You can match those three groups separately, and make sure that they all present. Also, [^\w] seems a bit too broad, but if that's what you want you might want to replace it with \W.
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