In the linux shell, the following command will recursively search and replace all instances of 'this' with 'that' (I don't have a Linux shell in front of me, but it should do).
find . -name "*.txt" -print | xargs sed -i 's/this/that/g'
What will a similar command on OSX look like?
When the -R option is used, MacOS grep requires you to explicitly give it a directory to search; for example, specify . to recursively search the current directory: grep -R 'networks' .
OS X uses a mix of BSD and GNU tools, so best always check the documentation (although I had it that less
didn't even conform to the OS X manpage):
https://web.archive.org/web/20170808213955/https://developer.apple.com/legacy/library/documentation/Darwin/Reference/ManPages/man1/sed.1.html
sed takes the argument after -i
as the extension for backups. Provide an empty string (-i ''
) for no backups.
The following should do:
find . -type f -name '*.txt' -exec sed -i '' s/this/that/g {} +
The -type f
is just good practice; sed will complain if you give it a directory or so.
-exec
is preferred over xargs
; you needn't bother with -print0
or anything.
The {} +
at the end means that find
will append all results as arguments to one instance of the called command, instead of re-running it for each result. (One exception is when the maximal number of command-line arguments allowed by the OS is breached; in that case find
will run more than one instance.)
If you get an error like "invalid byte sequence," it might help to force the standard locale by adding LC_ALL=C
at the start of the command, like so:
LC_ALL=C find . -type f -name '*.txt' -exec sed -i '' s/this/that/g {} +
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With