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I need to generate a random port number between 2000-65000 from a shell script. The problem is $RANDOM is a 15-bit number, so I'm stuck!
PORT=$(($RANDOM%63000+2001)) would work nicely if it wasn't for the size limitation.
Does anyone have an example of how I can do this, maybe by extracting something from /dev/urandom and getting it within a range?
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$1 means an input argument and -z means non-defined or empty. You're testing whether an input argument to the script was defined when running the script. Follow this answer to receive notifications.
You can iterate the sequence of numbers in bash in two ways. One is by using the seq command, and another is by specifying the range in for loop. In the seq command, the sequence starts from one, the number increments by one in each step, and print each number in each line up to the upper limit by default.
shuf -i 2000-65000 -n 1 Enjoy!
Edit: The range is inclusive.
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On Mac OS X and FreeBSD you may also use jot:
jot -r 1 2000 65000 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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