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When I use lineinfile in ansible it is not writing ', " characters
lineinfile: 'dest=/home/xyz state=present line="CACHES="default""'
it is giving CACHES=default
but the desired output is CACHES="default"
How to achieve this?
733
To modify a line, you need to use the Ansible backrefs parameter along with the regexp parameter. This should be used with state=present. If the regexp does not match any line, then the file is not changed. If the regexp matches a line or multiple lines, then the last matched line will be replaced.
In '\'' first ' closes string, then \' glues escaped single quote, then ' starts next string to be glued.
it appears you can escape the quotes:
- lineinfile: dest=/tmp/xyz state=present line="CACHES=\"default\""
That gives this output:
$ cat /tmp/xyz
CACHES="default"
You don't need to escape single quotes that are inside double quotes:
- lineinfile: dest=/tmp/xyz state=present line="CACHES=\"default\" foo='x'"
cat /tmp/xyz
CACHES="default" foo='x'
source: YAML specification, stackoverflow answer
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