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How can I apply an offset on the current time in python?
In other terms, be able to get the current time minus x hours and/or minus m minutes and/or minus s secondes and/or minus ms milliseconds
for instance
curent time = 18:26:00.000 offset = 01:10:00.000 =>resulting time = 17:16:00.000 
212
The utcoffset() function is used to return a timedelta object that represents the difference between the local time and UTC time. This function is used in used in the datetime class of module datetime. Here range of the utcoffset is “timedelta(hours=24) <= offset <= timedelta(hours=24)”.
To remove timestamp, tzinfo has to be set None when calling replace() function. First, create a DateTime object with current time using datetime. now(). The DateTime object was then modified to contain the timezone information as well using the timezone.
The datetime. strptime() sets the hour and minute values to the default, 0 . Note that for a two-digit year (like 15 ) you'd use %y , not %Y , which is for a four-digit year. if you need to add an amount that is negative or more than one day then only the timedelta() solution would work.
Python timedelta() function is present under datetime library which is generally used for calculating differences in dates and also can be used for date manipulations in Python. It is one of the easiest ways to perform date manipulations. Code #1: Python3.
Use a datetime.datetime(), then add or subtract datetime.timedelta() instances.
>>> import datetime >>> t = datetime.datetime.now() >>> t - datetime.timedelta(hours=1, minutes=10) datetime.datetime(2012, 12, 26, 17, 18, 52, 167840) timedelta() arithmetic is not supported for datetime.time() objects; if you need to use offsets from an existing datetime.time() object, just use datetime.datetime.combine() to form a datetime.datetime() instance, do your calculations, and 'extract' the time again with the .time() method:
>>> t = datetime.time(1, 2) >>> dt = datetime.datetime.combine(datetime.date.today(), t) >>> dt datetime.datetime(2012, 12, 26, 1, 2) >>> dt -= datetime.timedelta(hours=5) >>> dt.time() datetime.time(20, 2) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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