R's which() and which.min() Equivalent in Python

Question

I read the similar topic here. I think the question is different or at least .index() could not solve my problem.

This is a simple code in R and its answer:

x <- c(1:4, 0:5, 11) x #[1]  1  2  3  4  0  1  2  3  4  5 11 which(x==2) # [1] 2 7 min(which(x==2)) # [1] 2 which.min(x) #[1] 5 

Which simply returns the index of the item which meets the condition.

If x be the input for Python, how can I get the indeces for the elements which meet criteria x==2 and the one which is the smallest in the array which.min.

x = [1,2,3,4,0,1,2,3,4,11]  x=np.array(x) x[x>2].index() ##'numpy.ndarray' object has no attribute 'index' 

Answer 1

Numpy does have built-in functions for it

x = [1,2,3,4,0,1,2,3,4,11]  x=np.array(x) np.where(x == 2) np.min(np.where(x==2)) np.argmin(x)  np.where(x == 2) Out[9]: (array([1, 6], dtype=int64),)  np.min(np.where(x==2)) Out[10]: 1  np.argmin(x) Out[11]: 4