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How do I go about running a bash script using the subprocess module, to which I must give several arguments?
This is what I'm currently using:
subprocess.Popen(['/my/file/path/programname.sh', 'arg1 arg2 %s' % arg3], \ shell = True) The bash script seems not to be taking any of the parameters in. Any insights are greatly appreciated!
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To pass multiple arguments to a shell script you simply add them to the command line: # somescript arg1 arg2 arg3 arg4 arg5 … To pass multiple arguments to a shell script you simply add them to the command line: # somescript arg1 arg2 arg3 arg4 arg5 …
NUM} ) in the 2^32 range, so there is a hard limit somewhere (might vary on your machine), but Bash is so slow once you get above 2^20 arguments, that you will hit a performance limit well before you hit a hard limit.
Setting the shell argument to a true value causes subprocess to spawn an intermediate shell process, and tell it to run the command. In other words, using an intermediate shell means that variables, glob patterns, and other special shell features in the command string are processed before the command is run.
You can pass the arguments to any bash script when it is executed. There are several simple and useful ways to pass arguments in a bash script. In this article guide, we will let you know about some very easy ways to pass and use arguments in your bash scripts.
Pass arguments as a list, see the very first code example in the docs:
import subprocess subprocess.check_call(['/my/file/path/programname.sh', 'arg1', 'arg2', arg3]) If arg3 is not a string; convert it to string before passing to check_call(): arg3 = str(arg3).
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