Python Selenium accessing HTML source

Question

You need to access the page_source property:

from selenium import webdriver

browser = webdriver.Firefox()
browser.get("http://example.com")

html_source = browser.page_source
if "whatever" in html_source:
    # do something
else:
    # do something else

from bs4 import BeautifulSoup
from selenium import webdriver

driver = webdriver.Chrome()
html_source_code = driver.execute_script("return document.body.innerHTML;")
html_soup: BeautifulSoup = BeautifulSoup(html_source_code, 'html.parser')

Now you can apply BeautifulSoup function to extract data...

driver.page_source will help you get the page source code. You can check if the text is present in the page source or not.

from selenium import webdriver
driver = webdriver.Firefox()
driver.get("some url")
if "your text here" in driver.page_source:
    print('Found it!')
else:
    print('Did not find it.')

If you want to store the page source in a variable, add below line after driver.get:

var_pgsource=driver.page_source

and change the if condition to:

if "your text here" in var_pgsource:

With Selenium2Library you can use get_source()

import Selenium2Library
s = Selenium2Library.Selenium2Library()
s.open_browser("localhost:7080", "firefox")
source = s.get_source()