The ValueError: math domain error is raised when you perform a mathematical function on a negative or zero number which cannot be computed. To solve this error, make sure you are using a valid number for the mathematical function you are using.
The domain of a function is the set of all possible input values. If Python throws the ValueError: math domain error, you've passed an undefined input into the math function. In our case, don't calculate the log of a negative number or zero, and it will resolve the error.
Domain errors occur when numeric expressions are mathematically undefined or cannot be represented numerically on the computer for reasons other than missing data. Two common examples are division by 0 and the square root of a negative number.
Your code is doing a log
of a number that is less than or equal to zero. That's mathematically undefined, so Python's log
function raises an exception. Here's an example:
>>> from math import log
>>> log(-1)
Traceback (most recent call last):
File "<pyshell#59>", line 1, in <module>
log(-1)
ValueError: math domain error
Without knowing what your newtonRaphson2
function does, I'm not sure I can guess where the invalid x[2]
value is coming from, but hopefully this will lead you on the right track.
you are getting math domain error for either one of the reason : either you are trying to use a negative number inside log function or a zero value.
You may also use math.log1p
.
According to the official documentation :
math.log1p(x)
Return the natural logarithm of 1+x (base e). The result is calculated in a way which is accurate for x near zero.
You may convert back to the original value using math.expm1
which returns e
raised to the power x, minus 1.
You are trying to do a logarithm of something that is not positive.
Logarithms figure out the base after being given a number and the power it was raised to. log(0)
means that something raised to the power of 2
is 0
. An exponent can never result in 0
*, which means that log(0)
has no answer, thus throwing the math domain error
*Note: 0^0
can result in 0
, but can also result in 1
at the same time. This problem is heavily argued over.
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