I am trying to open a raw socket with Python under linux.
My simple code:
s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_IP)
s.bind((HOST, 5454))
And I got this error:
[ERROR] Protocol not supported
By the way, I am using python 2.7.3 under linux 12.04, and I used root to run the code.
Does anyone have a clue?
Update: The solution given by dstromberg is correct. If you want the whole packet, then use his solution. However, there is another combination:
s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP)
that also works.
In this case, you will receive a whole TCP packet with IP and TCP headers on it. If your use dstromberg's solution, you will also see the ethernet header. So it depends on how 'raw' you want your packet to be.
Raw socket is a layer 2 python library for communication using the MAC addresses only. This allows you to create a custom made Ethernet/WiFi communication system which is not using IP nor TCP/UDP or to debug custom frames such as SERCOS III, Profibus, ARP, PTP, ...
If you need access to the raw link layer, raw sockets on most OSes don't support that (Linux and Irix being obvious exceptions, as per the previous paragraph), but libpcap does. On Windows, it uses a lower-level network driver to capture data. RAW sockets are restricted to admin users on modern versions of Windows.
Raw sockets allow new IPv4 protocols to be implemented in user space. A raw socket receives or sends the raw datagram not including link level headers. The IPv4 layer generates an IP header when sending a packet unless the IP_HDRINCL socket option is enabled on the socket.
A raw socket is a type of socket that allows access to the underlying transport provider. This topic focuses only on raw sockets and the IPv4 and IPv6 protocols. This is because most other protocols with the exception of ATM do not support raw sockets.
Try socket.AF_PACKET instead of socket.AF_INET.
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