Can my server module (with http.server.HTTPServer
) use something like the RewriteRule
for redirect all traffic into a single cgi script? I'd like to be able to do what's shown here in this other question, but for my python server.
Can it be done using something like .htaccess
, or is there another way?
Also, can this be done even for a simple localhost development server?
I am serving files for development via, for example, http://localhost:8000/html/index.html, and I would like to hide the /html subfolder from the URL even in development.
How can that be achieved?
John Moutafis's answer was helpful to get me started, but needed some fine tuning to run on python3, beyond his comments about imports.
The imports should be
from http.server import HTTPServer, SimpleHTTPRequestHandler
and you'll also need to change the urllib import to:
from urllib.parse import unquote
Then the main should be something like:
if __name__ == '__main__':
myServer = HTTPServer(('0.0.0.0', 8000), RequestHandler)
print("Ready to begin serving files.")
try:
myServer.serve_forever()
except KeyboardInterrupt:
pass
myServer.server_close()
print("Exiting.")
You can use a custom script to initialize your server and define your Routes in it, such as suggested in this article:
Python 2:
server.py
import os import posixpath import urllib import BaseHTTPServer from SimpleHTTPServer import SimpleHTTPRequestHandler # modify this to add additional routes ROUTES = ( <- this is the "good stuff", make aliases for your paths # [url_prefix , directory_path] ['/media', '/var/www/media'], ['', '/var/www/site'] # empty string for the 'default' match ) class RequestHandler(SimpleHTTPRequestHandler): def translate_path(self, path): """translate path given routes""" # set default root to cwd root = os.getcwd() # look up routes and set root directory accordingly for pattern, rootdir in ROUTES: if path.startswith(pattern): # found match! path = path[len(pattern):] # consume path up to pattern len root = rootdir break # normalize path and prepend root directory path = path.split('?',1)[0] path = path.split('#',1)[0] path = posixpath.normpath(urllib.unquote(path)) words = path.split('/') words = filter(None, words) path = root for word in words: drive, word = os.path.splitdrive(word) head, word = os.path.split(word) if word in (os.curdir, os.pardir): continue path = os.path.join(path, word) return path if __name__ == '__main__': BaseHTTPServer.test(RequestHandler, BaseHTTPServer.HTTPServer)
Then run your script:
python server.py
Python 3:
In Python 3 the BaseHTTPServer
and the SimpleHTTPServer
modules have been merged into the http.server
module. So you will have to modify the above script as follows:
Change the
import BaseHTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler
to
import http.server
(if you do this then the calls should be modified to http.server.SimpleHTTPRequest
etc.)
or
from http.server import BaseHTTPServer, SimpleHTTPServer, SimpleHTTPRequestHandler
(with this option calls remain the same as the original script)
then run the server script: python server.py
You should modify the ROUTES
variable to suite your needs.
For example, you want to hide the /html
folder from your url:
ROUTES = (
['', '/exact/path/to/folder/html'],
['/another_url_path', '/exact/path/to/another/folder'],
...
)
Now if you hit: http://localhost:8000/index.html
you will be in your home page.
Note:
This script by default will serve the contained files in the folder that is in when executed to the domain url (ex. I have server.py
on the Documents folder, then when I run it, http://localhost:8000 url will server my Documents folder).
You can change this behavior by the Routes (see the 'default' match comment on the code) or by placing the script in your projects root folder and start it from there.
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