I have a file with the following path : D:/bar/クレイジー・ヒッツ!/foo.abc
I am parsing the path from a XML file and storing it in a variable called path
in the form of file://localhost/D:/bar/クレイジー・ヒッツ!/foo.abc
Then, the following operations are being done :
path=path.strip()
path=path[17:] #to remove the file://localhost/ part
path=urllib.url2pathname(path)
path=urllib.unquote(path)
The error is :
IOError: [Errno 2] No such file or directory: 'D:\\bar\\\xe3\x82\xaf\xe3\x83\xac\xe3\x82\xa4\xe3\x82\xb8\xe3\x83\xbc\xe3\x83\xbb\xe3\x83\x92\xe3\x83\x83\xe3\x83\x84\xef\xbc\x81\\foo.abc'
Update 1 : I am using Python 2.7 on Windows 7
Use open() to open a file in a different directory Join path with filename into a path to filename from the current directory. Call open(file) with file as the resultant path to filename to open filename from the current directory.
The error FileNotFoundError occurs because you either don't know where a file actually is on your computer. Or, even if you do, you don't know how to tell your Python program where it is. Don't try to fix other parts of your code that aren't related to specifying filenames or paths.
Run it with the python (or python3 ) command. You can get the absolute path of the current working directory with os. getcwd() and the path specified with the python3 command with __file__ . In Python 3.8 and earlier, the path specified by the python (or python3 ) command is stored in __file__ .
Provide the filename as a unicode
string to the open
call.
How do you produce the filename?
Add a line near the beginning of your script:
# -*- coding: utf8 -*-
Then, in a UTF-8 capable editor, set path
to the unicode
filename:
path = u"D:/bar/クレイジー・ヒッツ!/foo.abc"
Retrieve the contents of the directory using a unicode
dirspec:
dir_files= os.listdir(u'.')
Open the filename-containing-file using codecs.open
to read unicode
data from it. You need to specify the encoding of the file (because you know what is the “default windows charset” for non-Unicode applications on your computer).
Do a:
path= path.decode("utf8")
before opening the file; substitute the correct encoding if not "utf8".
The path in your error is:
'\xe3\x82\xaf\xe3\x83\xac\xe3\x82\xa4\xe3\x82\xb8\xe3\x83\xbc\xe3\x83\xbb\xe3\x83\x92\xe3\x83\x83\xe3\x83\x84\xef\xbc\x81'
I think this is the UTF8 encoded version of your filename.
I've created a folder of the same name on Windows7 and placed a file called 'abc.txt' in it:
>>> a = '\xe3\x82\xaf\xe3\x83\xac\xe3\x82\xa4\xe3\x82\xb8\xe3\x83\xbc\xe3\x83\xbb\xe3\x83\x92\xe3\x83\x83\xe3\x83\x84\xef\xbc\x81'
>>> os.listdir('.')
['?????\xb7???!']
>>> os.listdir(u'.') # Pass unicode to have unicode returned to you
[u'\u30af\u30ec\u30a4\u30b8\u30fc\u30fb\u30d2\u30c3\u30c4\uff01']
>>>
>>> a.decode('utf8') # UTF8 decoding your string matches the listdir output
u'\u30af\u30ec\u30a4\u30b8\u30fc\u30fb\u30d2\u30c3\u30c4\uff01'
>>> os.listdir(a.decode('utf8'))
[u'abc.txt']
So it seems that Duncan's suggestion of path.decode('utf8')
does the trick.
Update
I can't test this for you, but I suggest that you try checking whether the path contains non-ascii before doing the .decode('utf8')
. This is a bit hacky...
ASCII_TRANS = '_'*32 + ''.join([chr(x) for x in range(32,126)]) + '_'*130
path=path.strip()
path=path[17:] #to remove the file://localhost/ part
path=urllib.unquote(path)
if path.translate(ASCII_TRANS) != path: # Contains non-ascii
path = path.decode('utf8')
path=urllib.url2pathname(path)
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