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I want to use a bunch of local variables defined in a function, outside of the function. So I am passing x=locals() in the return value.
How can I load all the variables defined in that dictionary into the namespace outside the function, so that instead of accessing the value using x['variable'], I could simply use variable.
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With CPython 2.7, using dict() to create dictionaries takes up to 6 times longer and involves more memory allocation operations than the literal syntax. Use {} to create dictionaries, especially if you are pre-populating them, unless the literal syntax does not work for your case.
Variables can't be dict values. Dict values are always objects, not variables; your numbers dict's values are whatever objects __first , __second , __third , and __fourth referred to at the time the dict was created. The values will never update on the dictionary unless you do it manually. when they change..
It definitely can have a list and any object as value but the dictionary cannot have a list as key because the list is mutable data structure and keys cannot be mutable else of what use are they.
Consider the Bunch alternative:
class Bunch(object): def __init__(self, adict): self.__dict__.update(adict) so if you have a dictionary d and want to access (read) its values with the syntax x.foo instead of the clumsier d['foo'], just do
x = Bunch(d) this works both inside and outside functions -- and it's enormously cleaner and safer than injecting d into globals()! Remember the last line from the Zen of Python...:
>>> import this The Zen of Python, by Tim Peters ... Namespaces are one honking great idea -- let's do more of those! If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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