I need to open all PDFs in a certain directory, so I first generate a list of the file paths using os.path:
filenames = [
normpath(join(directoryname, filename))
for filename in listdir(directoryname)
if filename.lower().endswith('.'+extension)
]
So an item in that list looks like this: D:\\Folder\\2010\\file.pdf
Then I'd like to open each file in a for-loop:
for file in filenames:
PdfFileReader(file(file, 'rb'))
but there seems to be an issue with the 2010, because I get this error:
IOError: [Errno 2] No such file or directory: 'D:\\Folder\\x810\\file.pdf'
I'd like to do something along the lines of
PdfFileReader(file(r'D:\\Folder\\2010\\file.pdf', 'rb'))
how would I do that in the above example where the path is passed as a variable? Or are there any better ways to do this?
I'm using Windows and Python 2.6.
Thanks in advance!
The backslash is special in C-style strings like Python uses, just like in C++, C#, and Java. Either use a double-backslash to say “yes, I really mean a backslash,” not the character code \201
, or use an r''
string that does not interpret backslash sequences:
'D:\\Folder\\2010\\file.pdf'
r'D:\Folder\2010\file.pdf'
Note that this issue does NOT come up with variables! Once you create a string correctly, it always keeps its value; it does NOT get re-interpreted, and have backslashes cause problems all over again, each time you pass the value to a function, so open(myvar)
should see exactly the same string you get when you print(myvar)
.
(I think that on Windows you may also be able to just use forward slashes, which require no special quoting:)
'D:/Folder/2010/file.pdf'
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