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python: how to send mail with TO, CC and BCC?

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How do you send an email with CC in Python?

Send Email with PythonThe sendmail() function does this. It requires you to specify the email address of the sender and receiver, along with the message. If your SMTP server requires authentication to send a message, you'll need to enter the credentials of your email account.

How do I send a bulk and CC email in Bcc?

You can send a mass email to more than one recipient using the BCC feature. Click the compose box, after composing your message, click on BCC and add all your recipients. This will send the emails to the recipients keeping email addresses hidden from each other.

What is CC in Python?

The distinction between TO, CC and BCC occurs only in the text headers. At the SMTP level, everybody is a recipient. TO - There is a TO: header with this recipient's address. CC - There is a CC: header with this recipient's address. BCC - This recipient isn't mentioned in the headers at all, but is still a recipient.


Email headers don't matter to the smtp server. Just add the CC and BCC recipients to the toaddrs when you send your email. For CC, add them to the CC header.

toaddr = '[email protected]'
cc = ['[email protected]','[email protected]']
bcc = ['[email protected]']
fromaddr = '[email protected]'
message_subject = "disturbance in sector 7"
message_text = "Three are dead in an attack in the sewers below sector 7."
message = "From: %s\r\n" % fromaddr
        + "To: %s\r\n" % toaddr
        + "CC: %s\r\n" % ",".join(cc)
        + "Subject: %s\r\n" % message_subject
        + "\r\n" 
        + message_text
toaddrs = [toaddr] + cc + bcc
server = smtplib.SMTP('smtp.sunnydale.k12.ca.us')
server.set_debuglevel(1)
server.sendmail(fromaddr, toaddrs, message)
server.quit()

Key thing is to add the recipients as a list of email ids in your sendmail call.

import smtplib
from email.mime.multipart import MIMEMultipart

me = "[email protected]"
to = "[email protected]"
cc = "[email protected],[email protected]"
bcc = "[email protected],[email protected]"

rcpt = cc.split(",") + bcc.split(",") + [to]
msg = MIMEMultipart('alternative')
msg['Subject'] = "my subject"
msg['To'] = to
msg['Cc'] = cc
msg.attach(my_msg_body)
server = smtplib.SMTP("localhost") # or your smtp server
server.sendmail(me, rcpt, msg.as_string())
server.quit()

As of Python 3.2, released Nov 2011, the smtplib has a new function send_message instead of just sendmail, which makes dealing with To/CC/BCC easier. Pulling from the Python official email examples, with some slight modifications, we get:

# Import smtplib for the actual sending function
import smtplib

# Import the email modules we'll need
from email.message import EmailMessage

# Open the plain text file whose name is in textfile for reading.
with open(textfile) as fp:
    # Create a text/plain message
    msg = EmailMessage()
    msg.set_content(fp.read())

# me == the sender's email address
# you == the recipient's email address
# them == the cc's email address
# they == the bcc's email address
msg['Subject'] = 'The contents of %s' % textfile
msg['From'] = me
msg['To'] = you
msg['Cc'] = them
msg['Bcc'] = they


# Send the message via our own SMTP server.
s = smtplib.SMTP('localhost')
s.send_message(msg)
s.quit()

Using the headers work fine, because send_message respects BCC as outlined in the documentation:

send_message does not transmit any Bcc or Resent-Bcc headers that may appear in msg


With sendmail it was common to add the CC headers to the message, doing something such as:

msg['Bcc'] = [email protected]

Or

msg = "From: [email protected]" +
      "To: [email protected]" +
      "BCC: [email protected]" +
      "Subject: You've got mail!" +
      "This is the message body"

The problem is, the sendmail function treats all those headers the same, meaning they'll get sent (visibly) to all To: and BCC: users, defeating the purposes of BCC. The solution, as shown in many of the other answers here, was to not include BCC in the headers, and instead only in the list of emails passed to sendmail.

The caveat is that send_message requires a Message object, meaning you'll need to import a class from email.message instead of merely passing strings into sendmail.


Don't add the bcc header.

See this: http://mail.python.org/pipermail/email-sig/2004-September/000151.html

And this: """Notice that the second argument to sendmail(), the recipients, is passed as a list. You can include any number of addresses in the list to have the message delivered to each of them in turn. Since the envelope information is separate from the message headers, you can even BCC someone by including them in the method argument but not in the message header.""" from http://pymotw.com/2/smtplib

toaddr = '[email protected]'
cc = ['[email protected]','[email protected]']
bcc = ['[email protected]']
fromaddr = '[email protected]'
message_subject = "disturbance in sector 7"
message_text = "Three are dead in an attack in the sewers below sector 7."
message = "From: %s\r\n" % fromaddr
    + "To: %s\r\n" % toaddr
    + "CC: %s\r\n" % ",".join(cc)
    # don't add this, otherwise "to and cc" receivers will know who are the bcc receivers
    # + "BCC: %s\r\n" % ",".join(bcc)
    + "Subject: %s\r\n" % message_subject
    + "\r\n" 
    + message_text
toaddrs = [toaddr] + cc + bcc
server = smtplib.SMTP('smtp.sunnydale.k12.ca.us')
server.set_debuglevel(1)
server.sendmail(fromaddr, toaddrs, message)
server.quit()