I have a list of dict that looks like this:
list=[{u'hello':['001', 3], u'word':['003', 1], u'boy':['002', 2]},
{u'dad':['007', 3], u'mom':['005', 3], u'honey':['002', 2]} ]
What I need is to iterate on my list in order to create list of tuples like this:
new_list=[('hello','001', 3), ('word','003',1), ('boy','002', 2)
('dad','007',3), ('mom', '005', 3), ('honey','002',2)]
NOTE! the numbers with the zeros ('001',003'... and so on) must be considerated as a string.
Is there anybody whom can help me?
You can use list comprehension for that:
new_list = [(key,)+tuple(val) for dic in list for key,val in dic.items()]
Here we iterate over all dic
tonaries in list
. For every dic
tionary we iterate over its .items()
and extract the key
and val
ue and then we construct a tuple for that with (key,)+val
.
Whether the values are strings or not is irrelevant: the list comprehension simply copies the reference so if the original elements were Foo
s, they remain Foo
s.
Finally note that the dictionaries are unordered, so the order is undetermined. However if a dictionary d1
occurs before a dictionary d2
, all the elements of the first will be placed in the list before the tuples of the latter. But the order of tuples for each individual dictionary is not determined.
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