import MySQLdb
db = MySQLdb.connect("localhost","root","password","database")
cursor = db.cursor()
cursor.execute("SELECT id FROM some_table")
u_data = cursor.fetchall()
>>> print u_data
((1320088L,),)
What I found on internet got me till here:
string = ((1320088L,),)
string = ','.join(map(str, string))
>>> print string
(1320088L,)
what I expect output to look like:
#Single element expected result
1320088L
#comma separated list if more than 2 elements, below is an example
1320088L,1320089L
Use itertools.chain_fromiterable()
to flatten your nested tuples first, then map()
to string and join()
. Note that str()
removes the L
suffix because the data is no longer of type long
.
>>> from itertools import chain
>>> s = ((1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088'
>>> s = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088,1232121,1320088'
Note, string
is not a good variable name because it is the same as the string
module.
I think the string
is a tuple
of tuple
containing long values.
>>> string = ((1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088'
>>>
e.g. with more than one value
>>> string = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088,1232121,1320088'
>>>
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