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Django custom context_processors in render_to_string method

Tags:

python

django

I'm building a function to send email and I need to use a context_processor variable inside the HTML template of the email, but this don't work.

Example:

def send_email(plain_body_template_name, html_body_template_name):
    plain_body = loader.render_to_string(plain_body_template_name, context)
    html_body = loader.render_to_string(html_body_template_name, context)
    email_msg = EmailMultiAlternatives(body=plain_body)
    email_msg.attach_alternative(html_body, 'text/html')
    email_message.send()

In my custom context_processor.py I just have a function that receive a HttpRequest and return a dict like {'foo': 'bar'}, and in the template I try to render using {{foo}}.

I added the context_processor in the TEMPLATE['OPTIONS']['context_processors'] too.

like image 586
Rodolpho Pivetta Sabino Avatar asked Sep 06 '16 01:09

Rodolpho Pivetta Sabino


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What is Context_processors Django?

context_processors is a list of dotted Python paths to callables that are used to populate the context when a template is rendered with a request. These callables take a request object as their argument and return a dict of items to be merged into the context.

What is render to string in Django?

render_to_string is a callable within the django. template. loader module of the Django project. get_template and select_template are a couple of other callables within the django. template.

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template. Context , but Django also comes with a subclass, django. template. RequestContext , that acts slightly differently. RequestContext adds a bunch of variables to your template context by default-things like the HttpRequest object or information about the currently logged-in user.


2 Answers

Assuming you're using the django backend in your TEMPLATE with

'BACKEND': 'django.template.backends.django.DjangoTemplates',

django is seeing that you haven't passed in a request and opting for a basic Context to wrap your dict instead of a RequestContext which will handle the context_processors you've defined.

You can probably get away with doing

html_body = loader.render_to_string(html_body_template_name, context, request=request)

but you'd need to pass in the request object.

This might not make sense though. Are you emailing the person making the request? Does the context make sense to include?

If your context processor doesn't need the request then I'd either make it a simple utility function (if it's only called here) or make the request parameter optional, import it into this module, and add it directly into the context

context = {"my_var": 1} context.update(your_extra_context()) loader.render_to_string(...)

There are some complicated ways of updating a Context() in layers, but I don't think that's necessary here.

like image 57
Alex Riina Avatar answered Sep 20 '22 05:09

Alex Riina


I had a similar problem - I needed to render template to string with context processor values, but at the same time request object was None (running command from console). Then I found this approach:

from django.template.loader import render_to_string
from django.template import RequestContext
from django.shortcuts import render

def index(request):
    if not request:
        context = {'param1':'value1'}
        return render_to_string('myapp/index.html', RequestContext(None, context))
    else:
        #render as usual
        render(request, 'myapp/index.html', context)
        pass

when you pass RequestContext instead of dictionary, it populates values of all context processors into the context. But request must be optional in all your context processors, otherwise this won't work.

like image 21
Sergey Avatar answered Sep 20 '22 05:09

Sergey