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How can one check if a variable is an instance method or not? I'm using python 2.5.
Something like this:
class Test: def method(self): pass assert is_instance_method(Test().method) 
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Using isinstance() function, we can test whether an object/variable is an instance of the specified type or class such as int or list. In the case of inheritance, we can checks if the specified class is the parent class of an object. For example, isinstance(x, int) to check if x is an instance of a class int .
Definition and Usage. The isinstance() function returns True if the specified object is of the specified type, otherwise False . If the type parameter is a tuple, this function will return True if the object is one of the types in the tuple.
In Python, the built-in functions type() and isinstance() help you determine the type of an object. type(object) – Returns a string representation of the object's type. isinstance(object, class) – Returns a Boolean True if the object is an instance of the class, and False otherwise.
inspect.ismethod is what you want to find out if you definitely have a method, rather than just something you can call.
import inspect def foo(): pass class Test(object): def method(self): pass print inspect.ismethod(foo) # False print inspect.ismethod(Test) # False print inspect.ismethod(Test.method) # True print inspect.ismethod(Test().method) # True print callable(foo) # True print callable(Test) # True print callable(Test.method) # True print callable(Test().method) # True callable is true if the argument if the argument is a method, a function (including lambdas), an instance with __call__ or a class.
Methods have different properties than functions (like im_class and im_self). So you want
assert inspect.ismethod(Test().method) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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