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I have a problem here. I have to print a column in a text file using awk. However, the columns are not separated by spaces at all, only using a single comma. Looks something like this:
column1,column2,column3,column4,column5,column6 How would I print out 3rd column using awk?
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The unquoted commas in the print part tell AWK to use the chosen field separator (in this case, a comma) when printing. Note the extra commas in quotes – that's how the blank columns are added. First a comma is printed, then $1, then a comma, then $2...
txt. If you notice awk 'print $1' prints first word of each line. If you use $3, it will print 3rd word of each line.
Just put your desired field separator with the -F option in the AWK command and the column number you want to print segregated as per your mentioned field separator. Show activity on this post. AWK works as a text interpreter that goes linewise for the whole document and that goes fieldwise for each line.
Try:
awk -F',' '{print $3}' myfile.txt Here in -F you are saying to awk that use , as the field separator.
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If your only requirement is to print the third field of every line, with each field delimited by a comma, you can use cut:
cut -d, -f3 file -d, sets the delimiter to a comma-f3 specifies that only the third field is to be printed
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