Suppose we have this data file.
john 32 maketing executive jack 41 chief technical officer jim 27 developer dela 33 assistant risk management officer
I want to print using awk
john maketing executive jack chief technical officer jim developer dela assistant risk management officer
I know it can be done using for
.
awk '{printf $1; for(i=3;i<=NF;i++){printf " %s", $i} printf "\n"}' < file
Problem is its long and looks complex.
Is there any other short way to print rest of the fields.
With space as the separator you could even generalize the solution; e.g., the following returns everything from the 3rd field: awk '{sub(/^[ ]*([^ ]+ +){2}/, ""); print $0}' It gets trickier with arbitrary field separators, though.
To place the space between the arguments, just add " " , e.g. awk {'print $5" "$1'} . However it is not recommended to parse output of ls command, since it's not reliable and output is for humans, not scripts. Therefore use alternative commands such as find or stat .
You can cut in awk using awk's function split . You can also filter records using a regex condition within awk, making grep and cut superfluous.
Set the field(s) you want to skip to blank:
awk '{$2 = ""; print $0;}' < file_name
Source: Using awk to print all columns from the nth to the last
Reliably with GNU awk for gensub() when using the default FS:
$ gawk -v delNr=2 '{$0=gensub("^([[:space:]]*([^[:space:]]+[[:space:]]+){"delNr-1"})[^[:space:]]+[[:space:]]*","\\1","")}1' file john maketing executive jack chief technical officer jim developer dela assistant risk management officer
With other awks, you need to use match() and substr() instead of gensub(). Note that the variable delNr above tells awk which field you want to delete:
$ gawk -v delNr=3 '{$0=gensub("^([[:space:]]*([^[:space:]]+[[:space:]]+){"delNr-1"})[^[:space:]]+[[:space:]]*","\\1","")}1' file john 32 executive jack 41 technical officer jim 27 dela 33 risk management officer
Do not do this:
awk '{sub($2 OFS, "")}1'
as the same text that's in $2 might be at the end of $1, and/or $2 might contain RE metacharacters so there's a very good chance that you'll remove the wrong string that way.
Do not do this:
awk '{$2=""}1' file
as it adds an FS and will compress all other contiguous white space between fields into a single blank char each.
Do not do this:
awk '{$2="";sub(" "," ")}1' file
as it hasthe space-compression issue mentioned above and relies on a hard-coded FS of a single blank (the default, though, so maybe not so bad) but more importantly if there were spaces before $1 it would remove one of those instead of the space it's adding between $1 and $2.
One last thing worth mentioning is that in recent versions of gawk there is a new function named patsplit() which works like split() BUT in addition to creating an array of the fields, it also creates an array of the spaces between the fields. What that means is that you can manipulate fields and the spaces between then within the arrays so you don't have to worry about awk recompiling the record using OFS if you manipulate a field. Then you just have to print the fields you want from the arrays. See patsplit() in http://www.gnu.org/software/gawk/manual/gawk.html#String-Functions for more info.
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