How to create bash alias with argument? [duplicate]

Question

I normally use ps -elf | grep proceesname to get a detailed description of the process named processname. I think that I have to write too much for this.

Now what i was thinking is to create a bash alias like

alias lsps='ps -elf | grep $1' 

which will give the above detailed description only by using lsps processname.

So, my question is how do I create a bash alias which accepts an argument.

PS: I know I can write a shell script for the above task but I was just wondering how to do it with bash alias.

Answer 1

Very simple;

alias lsps='ps -elf | grep' 

Command line arguments will be added automatically to the end of the alias:

lsps arg1 arg2 arg3 => converted to => ps -elf | grep arg1 arg2 arg3 

That works only when you want to add arguments to the end of alias.

If you want to get arguments of the alias inside of the expanded command line you must use functions:

For example:

lsps() {     ps -elf | grep "$1" | grep -v grep } 

Functions as well as aliases can be saved in your ~/.bashrc file )or a file that is included from it):

$ cat /tmp/.bash_aliases lsps() {     ps -elf | grep "$1" | grep -v grep }  $ . /tmp/.bash_aliases $ 

Answer 2

Use this:

alias lsps='ps -elf | grep' 

Then you can issue this:

lsps processname