Print Hex With Spaces Between

Question

I'm trying to print my hex out in another way...

First I'm converting this (bytestring is the name of the variable):

b'\xff\x00\xff\xff\xff'

to hex,

print(bytestring.hex())

which outputs:

ff00ffffff

but I've been trying for a while to get it to output this:

ff 00 ff ff ff

but no luck.

Any suggestions? Cheers!

---

Update:

stringdata = f.read(5)
print(stringdata)
#b'\xff\x00\xff\xff\xff'

readHex = " ".join(["{:02x}".format(x) for x in stringdata.hex()])
# ValueError: Unknown format code 'x' for object of type 'str'

Answer 1

In Python 3.8+, hex function has an optional argument splitter.

>>> print(b'\xff\x00\xff\xff\xff'.hex(' '))
'ff 00 ff ff ff'

And you can split the hex string with any character you want.

>>> print(b'\xff\x00\xff\xff\xff'.hex(':'))
'ff:00:ff:ff:ff'

Answer 2

just convert your array of bytes to hex strings, and join the result with space:

>>> d=b'\xff\x00\xff\xff\xff'
>>> " ".join(["{:02x}".format(x) for x in d])
'ff 00 ff ff ff'

note that " ".join("{:02x}".format(x) for x in d) would also work, but forcing the list creation is faster as explained here: Joining strings. Generator or list comprehension?

In python 2, bytes is str so you have to use ord to get character code

>>> " ".join(["{:02x}".format(ord(x)) for x in d])

Answer 3

Seems like the community does not agree that this is a dupe, so I'll post my comment as an answer.

You can convert to a string:

bytestring = str(b'\xff\x00\xff\xff\xff').encode('hex')
print(bytestring)
#ff00ffffff

Then iterate over it in chunks of 2, and join the chunks with a space:

print(" ".join([bytestring[i:i+2] for i in range(0, len(bytestring), 2)]))
#'ff 00 ff ff ff'