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Print all day-dates between two dates [duplicate]

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How do I generate all dates between two dates?

We can get the dates between two dates with single method call using the dedicated datesUntil method of a LocalDate class. The datesUntill returns the sequentially ordered Stream of dates starting from the date object whose method is called to the date given as method argument.

How do I get all the days between two dates in Python?

You can use simple date arithmetic to find the number of days between two dates in Python. Define the 2 dates between which you want to find the difference in days. Then subtract these dates to get a timedelta object and examine the day's property of this object to get the required result.

How can I print the date between two dates in PHP?

$dates = getBetweenDates('2021-11-01', '2021-11-10'); print_r($dates);


I came up with this:

from datetime import date, timedelta

start_date = date(2008, 8, 15) 
end_date = date(2008, 9, 15)    # perhaps date.now()

delta = end_date - start_date   # returns timedelta

for i in range(delta.days + 1):
    day = start_date + timedelta(days=i)
    print(day)

The output:

2008-08-15
2008-08-16
...
2008-09-13
2008-09-14
2008-09-15

Your question asks for dates in-between but I believe you meant including the start and end points, so they are included. To remove the end date, delete the "+ 1" at the end of the range function. To remove the start date, insert a 1 argument to the beginning of the range function.


Using a list comprehension:

from datetime import date, timedelta

d1 = date(2008,8,15)
d2 = date(2008,9,15)

# this will give you a list containing all of the dates
dd = [d1 + timedelta(days=x) for x in range((d2-d1).days + 1)]

for d in dd:
    print d

# you can't join dates, so if you want to use join, you need to
# cast to a string in the list comprehension:
ddd = [str(d1 + timedelta(days=x)) for x in range((d2-d1).days + 1)]
# now you can join
print "\n".join(ddd)

Essentially the same as Gringo Suave's answer, but with a generator:

from datetime import datetime, timedelta


def datetime_range(start=None, end=None):
    span = end - start
    for i in xrange(span.days + 1):
        yield start + timedelta(days=i)

Then you can use it as follows:

In: list(datetime_range(start=datetime(2014, 1, 1), end=datetime(2014, 1, 5)))
Out: 
[datetime.datetime(2014, 1, 1, 0, 0),
 datetime.datetime(2014, 1, 2, 0, 0),
 datetime.datetime(2014, 1, 3, 0, 0),
 datetime.datetime(2014, 1, 4, 0, 0),
 datetime.datetime(2014, 1, 5, 0, 0)]

Or like this:

In []: for date in datetime_range(start=datetime(2014, 1, 1), end=datetime(2014, 1, 5)):
   ...:     print date
   ...:     
2014-01-01 00:00:00
2014-01-02 00:00:00
2014-01-03 00:00:00
2014-01-04 00:00:00
2014-01-05 00:00:00

import datetime

d1 = datetime.date(2008,8,15)
d2 = datetime.date(2008,9,15)
diff = d2 - d1
for i in range(diff.days + 1):
    print (d1 + datetime.timedelta(i)).isoformat()

import datetime

begin = datetime.date(2008, 8, 15)
end = datetime.date(2008, 9, 15)

next_day = begin
while True:
    if next_day > end:
        break
    print next_day
    next_day += datetime.timedelta(days=1)