Pointer will not work in printf()

Question

Having an issue with printing a pointer out. Every time I try and compile the program below i get the following error:

pointers.c:11: warning: format ‘%p’ expects type ‘void *’, but argument 2 has type ‘int *’ 

I'm obviously missing something simple here, but from other examles of similar code that I have seen, this should be working.

Here's the code, any help would be great!

#include <stdio.h>      int main(void)     {        int x = 99;        int *pt1;         pt1 = &x;         printf("Value at p1: %d\n", *pt1);        printf("Address of p1: %p\n", pt1);         return 0;     } 

Answer 1

Simply cast your int pointer to a void one:

printf( "Address of p1: %p\n", ( void * )pt1 ); 

Your code is safe, but you are compiling with the -Wformat warning flag, that will type check the calls to printf() and scanf().