How to pass ENUM as function argument in C

Question

I have an enum declared as;

typedef enum  {    NORMAL = 0,               EXTENDED                }CyclicPrefixType_t;  CyclicPrefixType_t cpType;   

I need a function that takes this as an argument :

fun (CyclicPrefixType_t cpType) ;   

func declaration is :

void fun(CyclicPrefixType_t cpType); 

Please help. I don't think it is correct.

Thanks

Answer 1

That's pretty much exactly how you do it:

#include <stdio.h>  typedef enum {     NORMAL = 31414,     EXTENDED } CyclicPrefixType_t;  void func (CyclicPrefixType_t x) {     printf ("%d\n", x); }  int main (void) {     CyclicPrefixType_t cpType = EXTENDED;     func (cpType);     return 0; } 

This outputs the value of EXTENDED (31415 in this case) as expected.

Answer 2

The following also works, FWIW (which confuses slightly...)

#include <stdio.h>  enum CyclicPrefixType_t {     NORMAL = 31414,     EXTENDED };  void func (enum CyclicPrefixType_t x) {     printf ("%d\n", x); }  int main (void) {     enum CyclicPrefixType_t cpType = EXTENDED;     func (cpType);     return 0; } 

Apparently it's a legacy C thing.